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A long wire carrying 4.50 A of current makes two 90 bends, as shown in the...

A long wire carrying 4.50 A of current makes two 90° bends, as shown in the figure

The bent part of the wire passes through a uniform 0.238 T magnetic field directed as shown in the figure and confined to a limited region of space.

Part A

Find the magnitude of the force that the magnetic field experts on the the wire.

Part B

Find the direction of the force that the magnetic field experts on the the wire.

The magnetic force on a current carrying conductor $$F=B I L \sin \theta$$

For the horizontal region,

$$F_{H}=0.238 \times 4.5 \times 0.6=0.64 \mathrm{~N}$$

Direction: The magnetic field faces outside the plane of paper, current to the right, hence the force downwards.

For the vertical region,

$$F_{V}=0.238 \times 4.5 \times 0.3=0.32 \mathrm{~N}$$

Direction: The magnetic field faces outside the plane of paper, current to the top, hence the force right.

Total force, $$F=\sqrt{(0.64)^{2}+(0.32)^{2}}=0.72 \mathrm{~N}$$

Direction: Clockwise from the right $$45^{\circ}$$

The final direction angle is wrong...

You take the inverse tan of Fx/Fy

answered by: Abby Bittner

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