Need help statistics question about adult smokers
A binomial experiment is a discrete probability experiment that satisfies the following conditions. The experiment is repeated for a fixed number of trails, each trail is independent of the other trails. There are two possible outcomes for each trail. The outcomes are classified as success (S) or as a failure (F).
The probability of success, p remains same for each trail. The random variable X represents the number of successes in n independent trails of the experiment.
The probability of success is known and number of trails is fixed. So, apply binomial distribution.
Let the random variable X follows a binomial distribution with parameters n and p.
The probability mass function (PMF) of binomial distribution can be defined as,
The mean and standard deviation of the random variable X is,
(a)
Let the random variable X represents the number of smokers who started before 18in 200 trails of the probability experiment.
Let represent the number of randomly selected adult smokers.
Let p=0.80 represent the proportion of adult smokers started smoking before turning 18 years old.
The possible outcomes are “Before turning 18 years old” or “After turning 18 years old.”
The experiment is repeated n times (countable finite).
The mean of the random variable X is,
The standard deviation of the random variable X is,
(b)
The expected value of the random variable X is considered as the mean of the random variable.
Hence, it is expected that in a random sample of 200 adult smokers, 160 will have started smoking before turning 18.
(c)
In part (a), the mean and standard deviation for the binomial variable are, and , respectively.
The 2 sigma limits for the smokers who started smoking before 18 are calculated as follows:
The value 170 lies between the 2 sigma limits.
Ans: Part aThe mean and standard deviation of the random variable X are and .
Part bIt is expected that in a random sample of 200 adult smokers, 160 will have started smoking before turning 18.
Part cNo, because 170 is lies between and.
Need help statistics question about adult smokers According to an almanac, 80% of adult smokers started...
statistics question about smoking before 18 years of ageAccording to an almanac, 70% of adult smokers started smoking before turning 18 years oh When technology is used, use the Tech Help button for further assistance. (a) Compute the mean and standard deviation of the random variable X, the number of smokers who started before 18 in 100 trials of the probability experiment (b) Interpret the mean.(c) Would it be unusual to observe 80 smokers who started smoking before turning 18 years old...
Question 11 2 pts 11. According to an almanac, 55% of adult smokers started smoking before turning 18 years old. Compute the standard deviation of the random variable X, the number of smokers who started before 18 in 300 trials of the probability experiment. Round your answer to one decimal place. 7.5 0 o 9.1 6.7 8.6
According to the Information Please Almanac, 80% of adultsmokers started smoking before turning 18 years old.a). Compute the mean and standard deviation of the randomvariable X, the number of smokers who started before 18 in 200trials of the probability experiment.b). Interpret the mean.c). Would it be unusual to observe 180 smokers who startedsmoking before turning 18 years old in a random sample of 200 adultsmokers? Why?
Seventy-five percent of adult smokers started smoking before turning 18 years old. If 20 adult smokers are randomly chosen, find the probability that at most 6 of them started smoking after they turned 18.
a) Compute the mean and standard deviation of the andom variable x the number of smokers who sarted smoking bofore 18 based on a random sample of 300 a b) interprat the mean oRound to the nearest terth as needed.) b) What is the comect Interpretation of the mean? OB tis expected thet in a random sample of 300 adulit smokers 180 will have started smoking bofore tuning 18 O C. tis expected that in a random sample of 300...
6 (20 pts) Imagine that you are a polister working for an Erie County Democratic Organization preparing for the 2020 presidential campaign. Suppose you take an early poll to see how the population of Hamburg NY, population 25,000, feels about former VP Joe Biden. From a random sample of 400 voters, 230 say they would vote for Biden. Calculate a 95 % confidence interval for the proportion of Hamburg voters likely to vote for Biden. Verify that the requirements for...
According to a consumer survey of young adults (18-24 years of age) who shop online, 29% own a mobile phone with internet access. In a random sample of 400 young adults who shop online, let x be the number who own a mobile phone with internet access. a. Explain why x is a binomial random variable (to a reasonable degree of approximation). Choose the correct explanation below. A. The experiment consists of n identical, dependent trials, with more than two...
According to a consumer survey of young adults (18-24 years of age) who shop online, 30% own a mobile phone with internet access. In a random sample of 400 young adults who shoponline, let x be the number who own a mobile phone with internet access. a. Explain why x is a binomial random variable (to a reasonable degree of approximation). Choose the correct explanation below. A. The experiment consists of n identical, dependent trials, where there are only two...
A Waist is a Terrible Thing to Mind: The waist circumference of males 20 to 29 years ele is approximately normally distributed, with mean 92.5 cm and standard deviation 13.5 Source: M.A. McDowell. CD. Fryar.R. Hirs for Children and Adults: U.S. Population. 1999-2002. Advance data from vital and health statistics: No. 361. Hyattsville, MD: National Center for Health Statistics, 2005. d CL. Ogden, Anthropometric Reference Data 5. Draw a normal curve with the parameters labeled. 92.5 What proportion of 20-...
Question 3 Math 117-017: Statistics Project Due Date: Wednesday, December 5th Description: A study was conducted at an American medical center regarding blood cholesterol levels and heart-attack incidents. A random sample of 30 heart-attack patients had their cholesterol levels measured two days after the attack. In addition, cholesterol levels were measured for a control group of 30 people who had not had a heart attack. The units of cholesterol measurement are mg/dl. of blood. The two data sets are below...