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# A charge of -5.92 μC is traveling at a speed of 5.16 × 106 m/s in...

A charge of -5.92 μC is traveling at a speed of 5.16 × 106 m/s in a region of space where there is a magnetic field. The angle between the velocity of the charge and the field is 57.4o. A force of magnitude6.76 × 10-3 N acts on the charge. What is the magnitude of the magnetic field?

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The magnetic force -

F=q(v x​​​​​​ B)

the magnitude-

F=qvBsin$\theta$ .............(1)

where $\theta$ is angle between velocity- of charge and the magnetic field=57.4°

velocity (v)=5.16x106m/s

charge (q)=-5.92μC=-5.92x10-6C

magnitude of force (F)=6.76x10-3N

using equation (1)-

6.76x10-3 =5.92x10-6 x 5.16x106 xBsin(57.4°)

B=2.63x10-4tesla Ans.

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