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Questions 1. Calculate the molarity of a sodium hydroxide (NaOH) solution that is titrated with 0.6887...

Questions 1. Calculate the molarity of a sodium hydroxide (NaOH) solution that is titrated with 0.6887 g of oxalic acid (Equa

Questions 1. Calculate the molarity of a sodium hydroxide (NaOH) solution that is titrated with 0.6887 g of oxalic acid (Equation 2). The titration requires 15.80 mL of the NaOH solution to reach the end point. Calculate the molarity of a sulfuric acid (H,SO) solution if 30.10 mL of 0.62 10 M NaOH is required to reach the end point when titrated against 10.00 mL of the unknown acid solution. The balanced chemical equation for the reaction is given below. (Refer to Example 2 for help with calculations) 2. Na,SO,(aq) + 2 H,00) H,SO,(aq) +2 NaOH(aq) -
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1.) males of oxalic acid = Mass - Do 68879 • Malau mass 90.03g/mas a males = 7. 65x10 mal C ₂ H ₂ O (aq) + 2Naoh (49) - Naz C2 2 Ron H₂SO4 (aq) + 2NaOH (ar) Nassou Can ) + 2H06) males of Naoh moles of He sou cofficient Molarity X 30x/03 Cofficiente -

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