Question

11. The solubility product constant for aluminum hydroxide (Al(OH)3) is 3.0 x 10”. Use the information...


11. The solubility product constant for aluminum hydroxide (Al(OH)3) is 3.0 x 10”. Use the information to calculate the molar
11. The solubility product constant for aluminum hydroxide (Al(OH)3) is 3.0 x 10”. Use the information to calculate the molar solubility of Aluminum hydroxide in: (a) pure water (6 points) 0.80 M KOH solution (4 points) 12. 20.0 mL of a 0.200 mol L solution of a metal ion M is mixed with 20.0 mL of a 0.300 mol I'' solution of a substance L. The following equilibrium is established: M (aq) + 2L (aq) + ML(aq) At equilibrium the concentration of L is found to be 0.0100 mol L". What is the equilibrium concentration of ML22*, in mol L '? (8 points)
0 0
Add a comment Improve this question
Answer #1


Ksp of Al(OH)} = 3.0 x16 34 In pure wate :- Alcoh }(s) — At Seag) + 30ti caq) 35 <sp = Cu+] Сонг23 3.0x1634 - SX(35) 3 S = 1.

Add a comment
Know the answer?
Add Answer to:
11. The solubility product constant for aluminum hydroxide (Al(OH)3) is 3.0 x 10”. Use the information...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT