# The electric field on the x axis due to a point charge fixed at the origin... The electric field on the x axis due to a point charge fixed at the origin is given by E = (b/x2)I, where b = 6.00 kv. m and x > 0. (a) Find the magnitude and sign of the point charge. 0.066 x nC positive (b) Find the potential difference between the points on the x axis at x V=-4 1.00 m and x 2.10 m. Which of these points is at the higher potential? 74%. O 1.00 m 2.10 m The points are at the same potential. #### Earn Coin

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