#= 162 xy^10z^12#
#(3y^2z^3)xx3(2xy^4z^3)#
Remove the brackets
#rarr# for the first one all the factors have go be cubed. #rarr# for the second, multiply by #3#
#=27y^6z^9xx6xy^4z^3" "larr # now multiply as usual
To multiply in algebra:
#27y^6z^9xx6xy^4z^3#
How do you simplify #(3y ^ { 2} z ^ { 3} ) ^ { 3} ( 2x y ^ { 4} z ^ { 3} )#?
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