# How do you solve (3x ^ { 2} - 4x ) = 4?

How do you solve (3x ^ { 2} - 4x ) = 4?

Answer 1

$x = - \frac{2}{3} \mathmr{and} x = - 2$

#### Explanation:

It is a quadratic equation (${x}^{2}$), so make it equal to $0$

$3 {x}^{2} - 4 x - 4 = 0$

Find factors if possible first.

$\left(3 x + 2\right) \left(x - 2\right) = 0$

Set each factor equal to $0$ and solve for $x$

If $3 x + 2 = 0 , \rightarrow x = - \frac{2}{3}$

If $x - 2 = 0 , \rightarrow x = 2$

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