Balance the redox equation for the oxidation of p-xylene to terephthalic acid using H2CrO4:

Question

Question

Balance the redox equation for the oxidation of p-xylene to terephthalic acid using H₂CrO₄:

How many milligrams of H₂CrO₄ are required to oxidize 75.0 mg of p-xylene to terephthalic acid?

Answer 1

Answer #1

Oxidation half reaction

p-xylene + H₂O terephthalic acid + 6 H⁺ + 6 e^-

Reduction half-reaction

H₂CrO₄ + 6 H⁺ + 3 e^- Cr³⁺ + 4 H₂O

Total reaction

C₈H₁₀ + 2 H₂CrO₄ + 6 H⁺ C₈H₆O + 2 Cr³⁺ + 7 H₂O

milligrams of H₂CrO₄ = 1.67 x 10³ mg (or 167 mg)

Answer 2

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