Question

# A 85 kg sky diver jumps out of a plane at an altitude of 700 m....

A 85 kg sky diver jumps out of a plane at an altitude of 700 m. After the skydiver falls for a period the parachute opens and lands with a speed of 3.6 m/s. What is the energy dissipated by the parachute during the dive? 75 kJ 14 kJ 114 kJ 1.8 kJ

If the parachute had not been used, landing speed would have been,

v = (2gh)1/2 = (2 * 9.81 * 700)1/2 = 117.2 m/s

Energy dissipated, E = 85 * (117.22 - 3.62) / 2 = 583 kJ

SOLUTION :

P. E. lost on reaching the ground

= m g h

= 85 * 9.8 * 700

= 583100 J

K. E. of the driver at  the time of landing

= 1/2 m v^2

= 1/2 * 85 * (3.6)^2

= 550.8 J

Energy dissipated by the parachute during dive

= 583100 - 550.8

= 582549.2 J

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