If the parachute had not been used, landing speed would have been,
v = (2gh)^{1/2} = (2 * 9.81 * 700)^{1/2} = 117.2 m/s
Energy dissipated, E = 85 * (117.2^{2} - 3.6^{2}) / 2 = 583 kJ
SOLUTION :
P. E. lost on reaching the ground
= m g h
= 85 * 9.8 * 700
= 583100 J
K. E. of the driver at the time of landing
= 1/2 m v^2
= 1/2 * 85 * (3.6)^2
= 550.8 J
Energy dissipated by the parachute during dive
= 583100 - 550.8
= 582549.2 J
= 583 kJ approx. (ANSWER)
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