- Questions & Answers
- + Post
- Get Expert Help
- Get Coins
12) False ( CSTR need larger reaction volume achieve the same reaction rate )
18) d(finely divided suspended material)
reply ma as soon as possible 120 points total Due: October 23, 2019 Budget your time...
(30 points) A completely mixed activated sludge system comprised of an aerated reactor and a secondary clarifier with sludge return is going to treat 15,000 m/d of industrial wastewater. The primary effluent going to the reactor has a BODs of 1,100 mg/L that must be reduced to 150 mg/L prior to discharge to a municipal sewer. The pilot study was conducted and generated the following results: 3. Mean cell residence time- 5 day, MLSS concentration in the reactor 7.200 mg/L...
A wastewater flow of 18,000 m3/day is to be treated in a completely mixed activated sludge system at a concentration of 3000 mg/L MLSS (mixed liquor suspended solids). The secondary clarifier is designed to thicken the sludge to 12,000 mg/L. Assuming a growth yield coefficient of 0.5 Kg/Kg, an influent BOD of 100 mg/L with a residence time of 8 days, determine the following: a) The volume of the reactor b) The mass of the solids and the wet volume...
Situation (note: Problem 2 is not linked with Problem 1): Assuming the design flow rate of raw wastewater to be treated is 20 MGD in the design year, the dissolved BODs is 380 mg/L, and SS is 360 mg/L. The wastewater generated by the sludge treatment process is about 4 MGD with the dissolved BODs being 1800 mg/L, and SS being 1200 mg/L, and will be returned to the wet well in the pumping station at the beginning of the...
CIEG 328 HOMEWORK7 Homework 7 (Suspended growth) Due: 4/112019 Design an activated sludge biological treatment system for a typical medium-strength domestic wastewater with a design daily flow of 2.9 million gallons per day. Assume the plant effluent criteria are 10/10/1" This means that the plant must produce an effuent with average BODS and TSS concentrations of 10 mg/Leach year round, and an effluent ammonia concentration of 1 mg/L as N during the winter months. The layout of the plant will...
A completely mixed activated sludge plant is designed to treat 10,000 m3/d of an industrial wastewater. The wastewater has a BOD5 of 1200 mg/L. Pilot plant data indicates that a reactor volume of 6090 m3 with an MLSS concentration of 5000 mg/L should produce 83% BOD5 removal. The value for Y is determined to be 0.7 kg/kg and the value of kd is found to be 0.03 d–1. Under ow solids concentra- tion is 12,000 mg/L. The ow diagram is...
2. A completely mixed activated sludge process is designed to treat 20,000 m/d of domestic wastewater having a BODs concentration of 250 mg/L following primary treatment. The NPDES permit requirement for effluent BODs and TSS is 20 mg/L for each. The biokinetic parameters have beern established as: yield 0.6, k 5/d, K-60 mg/L, and kd 0.06/d. The MLVSS concentration in the aeration tank is to be maintained at 3000 mg/L and the ratio of VSS/TSS is 0.75. Assume that the...
A complete-mix activated sludge system is used to treat municipal wastewater after primary sedimentation at 20 °C with MLVSS concentration of 2000 g/m3. The discharge standard for soluble BOD, concentration in the effluent is 0.5 g/m. The characteristics of the primary influent are: flow Q -2000 m'/d, soluble BOD -200 g/m3, Using these data and the kinetic coefficients in following, determine 1. Theoretical solids retention time (SRT) in unit of days 2. Pk vss in unit of kg VSS/d 3....
nment #2 (Part A & B) Assigned: 01/23/2019 Due Date: 02/01/2019 Total Points 110 Part B A completely mixed flow reactor is to be designed to treat an influent stream with a COD concentration of 250 mg/L and a flow rate of 150 gallons per minute (GPM). Assume COD removal reaction has a degradation rate constant of 0.38 h1. Determine the hydraulic detention time (in hours) for the reactor and the volume of the reactor in ftIf the effluent COD...
2.  A small town has been directed to upgrade its primary wastewater treatment plant to a secondary plant that can meet an effluent standard of 25.0 mg/L BODs and 30.0 mg/L suspended solids. They have selected a completely mixed activated sludge system. The following data are available from the existing primary plant. Existing plant effluent characteristics Flow = 0.2000 m 3/s soluble BODs-80 mg/L Assume that the BOD5 of the suspended solids may be estimated as equal to 50%...
7. You work for the Ministry of Environment to evaluate the maximum ultimate BOD concentration in the effluent of a new wastewater treatment plant such that the oxygen deficit never exceeds 1.5 mg/L in the receiving river. During dry weather (i.e., lowest river flow), the wastewater will be diluted 10 times in the river water and the river water contains 3.5 mg/L of ultimate BOD. Also during dry weather, you know that the river velocity after the wastewater discharge would...