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C1= 5 C2= 6 C3= 10 GCD --> Greater Common Divisor B1 a. Let x :=...

C1= 5

C2= 6

C3= 10

GCD --> Greater Common Divisor

B1 a. Let x := 3C1 + 1 and let y := 5C2 + 1. Use the Euclidean algorithm to determine the GCD (x, y), and we denote this inte

B1 a. Let x := 3C1 + 1 and let y := 5C2 + 1. Use the Euclidean algorithm to determine the GCD (x, y), and we denote this integer by g. b. Reverse the steps in this algorithm to find integers a and b with ax + by = g. c. Use this to find the inverse of x modulo y. If the inverse doesn't exist why not? B2 a. Show that for integers a, b E Z, (a,b) = Cz implies (C3, b) > C1. b. Let n be the product of the first C primes (those of smallest sizes). What is the smallest number of possible prime divisors to check whether n + 1 is also a prime?
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soin B1. Giren 4-5 (-6C = 10 a. x=39+ 1 2-3 (5) +1 16 & y = 562+1 g 5(6) +1 31 by Euclidean algorithm. To find • GCD (NY) Con

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