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Procedure: Fire a practice shot. Locate the landing point on the floor then secure a piece...

Procedure: Fire a practice shot. Locate the landing point on the floor then secure a piece of white paper to the floor (centeProcedure: Latch the pendulum arm at 909 so that it is out of the way and use the plunger to push the steel sphere. Make sure1. Data Analysis with a detailed description of all calculation for the part I and II a) Find the initial speed using the dat

Procedure: Fire a practice shot. Locate the landing point on the floor then secure a piece of white paper to the floor (centered about the landing point). Cover the sheet with a piece of carbon paper and tape it down. 1. Shoot the ball at least 5 times. Take care not to disturb the position of the launcher during the shots. 2. Measure the vertical height H of the projectile launcher from the floor. (Use a plumb bob determine the true vertical distance to the floor). Record value in the Table. 3. Measure the horizontal displacement R for each trial and record values in the table. 4. Calculate the average <R> of the horizontal distance. 5. Find the initial velocity vo of the projectile using the < R > and H values. Data Table 1: Trial # Range R(m) 1 2.260 2.264 Vertical Height H = 0.925 m Absolute error in distance 4 H = AR = 0.001 m Horizontal range <R>=__2.262_(m) Time of flight t = _0.925 (sec) Initial Velocity v=-11.966 (m/s) +-0.005 2 3 2.280 4 2.254 5 2.250 <R>= 2.262 m Part II: Ballistic Pendulum Method yo Page 3 of 7
Procedure: Latch the pendulum arm at 909 so that it is out of the way and use the plunger to push the steel sphere. Make sure the ball is in contact with the plunger. Allow the pendulum to hang freely and move the angle indicator to zero degrees. After firing, can be read directly from the indicator There is some significant error caused by friction in the angle indicator. You can minimize it by making one measurement of and then setting the indicator to an angle a few degrees below this value. In this way the indicator does not have to slide as far. Using the angle measurements and the pendulum length Rem, determine the vertical displacement h values for each trial. Record in the table below: Data for part 2: The absolute error in mass Am = AM = +0.00001 Kg The absolute error in angle is 40 = +1° Absolute error in the length of the pendulum ARCM = +0.001m Mass of the metal ball (mp) 0.06586 Kg Mass of the pendulum(M) 0.24709 Kg Total Mass (M = mp+Mp)_ 0.31295 kg Length of the pendulum (Rcm) 0.290 m Rem is the distance between the center of mass of the pendulum-ball system and the axis of rotation of the pendulum. Data Table 2 Trial Angle (0) 35 1 2 3 h=Rcm (1-сos ) 0.0524 0.0554 0.0554 0.0554 0.0524 <h> = 0.0542 +-0.011 36 36 36 35 <>= 35.6+-1 4 5
1. Data Analysis with a detailed description of all calculation for the part I and II a) Find the initial speed using the data from part I for the projectile method. Show all work. Do not forget to include the absolute uncertainty in the velocity. b) Use the average height and the average angle calculated above in part II to find the initial speed of the ball. Include the absolute uncertainty in the initial velocity. Also, in your lab report include the answers to the following questions: 2. Are the values you obtained for the initial speeds using two different methods consistent with each other? Consider assumptions and uncertainties. If they are different, discuss the possible sources of error. 3. Is the kinetic energy conserved in the collision? If not, then what percentage of energy is "lost" in the collision between the steel ball and the pendulum? What happens to the remaining energy?
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Part I:- Table & Average range Page <R> - 2.260+ 2.264+ 2.280 + 2-254+ 2-25 5 le = 0.925 m ( 9 9.8 Qe(a) t KRY = 2.2616 (ans)2 192 For foail 1, 0= 35° h = 0.290 (1-C02 35) = 0.052 h = 0.0524 For troul 2, O = 36° h= 0.290(1- Cos 360) = 0.0554 h = 0.03 5 ogle so = 11 Initial veloci Where h is are + 0.001 aug oo quenoje 0: <0) - 35136+36+36735 g- {0} = 35.6 Vanilkal displacePg. Ab, erood in velocely. Av=g (sh Jh173 Dre! (0.011) (0.0542):\/2 Sv=0.0236 de initial velocity U= (1-03+0.0236)m/s Cans.Note:please don't give dislike .......please comment if you have any problem i will try to solve your problem...... please give thumbs up i am in need....

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