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1. Given data:
M = 3.10 M
V = 2.30 L
Molar mass of KCl = (39 + 35.5 ) g/mol = 74.5 g/mol
Molarity (M) = no. of moles of solute (n) / volume of solution V in litre ------- (1)
no. of moles (n) = given mass / Molar mass --------(2)
Using equation (2) in equation (1)
M = (given mass / molar mass ) / V
3.10 = (given mass / 74.5) / 2.30
given mass = 531.18 g of KCl
Correct option is third (532 g).
2. H2O (l) + H2O (l) H3O+ (aq) + OH- (aq)
K = [H3O+ (aq)] [OH- (aq)] / [H2O (l)] [H2O (l)]
Concentration of water is taken as 1 as it is in pure liquid form and in huge amount.
Kw = [H3O+ (aq)] [OH- (aq)] = 1.00 x 10-14
Correct option is third.
3. Gases are easily compressible as molecules have great distances between each other and due to which they can be stored under high pressure and a small container can contain large volume of gas.
Correct option is fourth (gases are compressible).
4. Kw = [H+] [OH-] = 10-14
[H+] = 10-14 / [OH-]
= 10-14 / 7.95 x 10-6
= 0.126 x 10-8 = 1.26 x 10-9 M
Correct option is first (1.26 x 10-9 M) .
A chemistry teacher needs to make 2.30 L of a potassium chloride solution for an experimen...
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