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A chemistry teacher needs to make 2.30 L of a potassium chloride solution for an experimen...



A chemistry teacher needs to make 2.30 L of a potassium chloride solution for an experimen The concentration of the required
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By titration, it is found that 87.1 mL of 0.153 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the concentration of the HCI solution. [HCI) M
0 0
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Answer #1

1. Given data:

M = 3.10 M

V = 2.30 L

Molar mass of KCl = (39 + 35.5 ) g/mol = 74.5 g/mol

Molarity (M) = no. of moles of solute (n) / volume of solution V in litre ------- (1)

no. of moles (n) = given mass / Molar mass --------(2)

Using equation (2) in equation (1)

M = (given mass / molar mass ) / V

3.10 = (given mass / 74.5) / 2.30

given mass = 531.18 g of KCl

Correct option is third (532 g).

2. H2O (l) + H2O (l)  \rightarrow H3O+ (aq) + OH- (aq)

K = [H3O+ (aq)] [OH- (aq)] / [H2O (l)] [H2​​​​​​​O (l)]

Concentration of water is taken as 1 as it is in pure liquid form and in huge amount.

Kw = [H3O+ (aq)] [OH- (aq)] = 1.00 x 10-14

Correct option is third.

3. Gases are easily compressible as molecules have great distances between each other and due to which they can be stored under high pressure and a small container can contain large volume of gas.

Correct option is fourth (gases are compressible).

4. Kw = [H+] [OH-] = 10-14

[H+] = 10-14 / [OH-]

= 10-14 / 7.95 x 10-6

= 0.126 x 10-8 = 1.26 x 10-9 M

Correct option is first (1.26 x 10-9 M) .

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