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Q3: Determine the vertical and horizontal displacement of joint A for the truss shown in Fig....


Q3: Determine the vertical and horizontal displacement of joint A for the truss shown in Fig. (3). each bar is made of steel
E D 2 m |в -1.5 m -1.5 m 20 KN 40 KN Fig. (3)
Q3: Determine the vertical and horizontal displacement of joint A for the truss shown in Fig. (3). each bar is made of steel and has the cross-sectional area of 400mm Take E = 200 GPa Use the method of virtual work.
E D 2 m |в -1.5 m -1.5 m 20 KN 40 KN Fig. (3)
0 0
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Answer #1

method of Joint FAE At Joint - A8 o = 53.139 A FAB Ostan in ) -53:13 40 kn 0 = 53.13 + +1€fy=0 FAE Sin (53:13) = 40 FALE 40At Joint Elo FED 112 10- 53.13 o A FAE FEC COSO = 0.6 sino - 0.8 for I &fa=0 FAE Coso = fee coso + FED 50 x 0.6 - Oro fec +FEremove all external loads kål values & apply IkH load at A in verti - cal direction a ter stenlos 2,5 m am 3 0 53.13 COSO=Joint Blo KBE 4 KAB KBC KBE = OK KBC = KAB KBC = -0.75 KM I J - At Joint Els KOE - A e = pefy = O 0 *KCE OKN KAE Sino+IBE+KCEki remore external loods horizontal lood at A -> apply const lood (hen) in Horizontal and apply 12 Pech 0-53-13 coso=0.6At Joint Els L2 داو AKDE o 4 Efy=0 t *KCE NC K AE Kae sino+kce sino +k8e = 0 KBE k (O) sine f KCE Sino + 0 = 0 klee = 0 km(u) load (P) Member k K Ct). Pkl Length (m) P.kl AE Cky 2 .Cm) AE (KM (kal AE cm2 - 30 -4. -5.625x16 8 X10 1.5 AB -0.75 1 4=) (SA) E Pkl AE - 104(4.2187 +42187+0+29.3 +2109 +19.53) = 104x (18.3574) m = 7.8357 mm (Salv 7.836 m Verhoceed T (San & Pk

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