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- Calculating the pH at equivalence of a titration A chemist titrates 180.0 ml of a 0.1215 M nitrous acid (HNO) solution with
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volume of HNO = 180m2 = 0-16 Lt Come at HNO2 = 0-1215 m. Cone of kom = 0.5476M - p19 = 3.35 & 4.46*10-4 .=Kq Reni HNO + koH KNO + H₂O 2 — Hng foto Core 0.096 Finally 0.096-2 Kar Kb = Kwon Kas 4,468104 Kb = 181044 = Kb = 4146x104 0.22 X10-10 - Now is=

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