(1 point) Use implicit differentiation to find the slope of the tangent line to the curve...
(1 point) Use implicit differentiation to find an equation of the tangent line to the curve 2xy3+xy=302xy3+xy=30 at the point (10,1)(10,1). (1 point) Use implicit differentiation to find an equation of the tangent line to the curve 2xy3 + xy = 30 at the point (10, 1). The equation -3/70 defines the tangent line to the curve at the point (10, 1).
Use implicit differentiation to find the slope of the tangent line to the curve 5x^3 y^2 - 4x^2 y = 1at the point (1,1) m=
use implicit differentiation to find the slope of the tangent line to the curve (y)/(x-7y)=x^6+5 at the point (1,6/43)
Find the equation of the tangent line to the curve at the given point using implicit differentiation. Remember: equation of a line can be found by y-y1=m(x-x1) where m is the slope of the line and (x1,y1) is any point on the line. Curve: at (1,1)
Use implicit differentiation to find the equation of the tangent line to the curve xy3+xy=14 at the point (7,1) . The equation of this tangent line can be written in the form y=mx+bi dont seem to no how to find m or b
Use implicit differentiation to find the equation of the tangent line to the curve xy^3+2xy=9 at the point (31). The equation of this tangent line can be written in the form y=mx+b where m is
Use implicit differentiation to find the equation of the tangent line to the curve xy^3+xy=5 at the point (4,1) . The equation of this tangent line can be written in the form y = mx+b where m is:? and where b is:?
Use implicit differentiation to find the equation of the tangent line at the given point. z? + x arctan y = y -2,
Use implicit differentiation to find an equation of the tangent line to the graph of the equation at the given point. x2 + x arctan y = y -
Use implicit differentiation to find the point in the first quadrant on the ellipse 8x? + 4y2 = 16.28125 where the slope of the tangent line is -0.1875. What is the x-coordinate of that point?