You perform the Simple Harmonic Motion experiment and create a plot of Period-Squared vs. Mass. You add a linear fit and find the following equation of the line: y=9.52x-0.067
What is the spring constant, k (in N/m or kg/s2)?
The time period of a SHM is
T = 2*pi * sqrt(m/k)
where m is the mass and k is the spring constant.
So, T^2 /m = 4*pi^2 /k
From the equation of the line, we can deduce that T^2 /m is nothing but the slope of the line.
So, T^2 /m = 9.52
So, 9.52 = 4*pi^2 /k
k = 4.15 N/m
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