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# Guestion 4 (1 point) A 34.1 gram piece of lead at 96.9。C is placed in a... Guestion 4 (1 point) A 34.1 gram piece of lead at 96.9。C is placed in a calorimeter oontaining water at 21.1°C. If the temperature at equilibrium is 27.8C, what is the mass of the water? Report your answer in grams to two (2) sig figs Your Answer: Answer units

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Answer #1

Heat lost by lead= heat gained by water

=> mlead x clead x (Tf -Ti) = mwater x Cwater x ( Tf - Ti)

=> 34.1 g x 0.160 J/g0C x( 96.9 -27.6)0C = mwater x 4.184 J/g0C x ( 27.6 - 21.1)0C

=> 378.1008 J = mwater x 27.196 J/g

=> mwater =( 378.1008 /27.196) g

=> mwater = 13.9 g = 14 g ( 2 sig. figures)

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