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Consider the molecule CF, in which the vibrational energy is 1285.77 cm-1. The temperature is 630.0...

Consider the molecule CF, in which the vibrational energy is 1285.77 cm-1. The temperature is 630.0 K. Assume that the molecule has constant vibrational energy spacing as described in the practice version of this question. Calculate the ratio of the population in the first excited state (n=1) to that in the ground state (n=0).

N1/N0=

Calculate the ratio of the population in the second excited state (n=2) to that in the ground state.

N2/N0=

Now calculate the ratio of the population in the first excited state to that in the ground state if the temperature increases to 880.0 K.

N1/N0=

Please Show All Work - for Phsyical Chemistry 2, Thank you!

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Answer #1

59, eme九0 A Paong between two guecess ive hey AE 0→ Ati-= emerga gap between t he two state 630o k I. 38 X 10-23 -2-556 X10 21丁 5-112X10 -20J.lo20丁 วา 0.0028 ← TI the temperature) T-680 ,ok 一 2-556X0-20 J T he mi 0 122If you still have any query, feel free to ask in the comments. If you like my work, please give a thumbs up.

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