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Calculate the pH of a buffer solution containing 0.100 M CH3COOH and 0.100 M CH3COONa ; Ka of CH3COOH = 1.8 x 10-5
Calculate the pH of a buffer solution containing 0.100 M CH3COOH and 0.100 M CH3COONa ;...
Which of the following pH values are within the buffer range for a buffer containing 0.5 M CH3COOH and 0.5 M CH3COONa? The Ka for CH3COO– is 1.8×10–5. Select any answers that apply. Multiple tries are permitted; however, 25% (1/4) point will be deducted for each incorrect response. Select one or more: 2.76 5.09 0.57 3.81 8.11
14) 14) Calculate the mole ratio of CH3COONa to CH3COOH required to make a buffer with pH of 4.83. Ka of CH3COOH is 1.8 x 10-5. A) 3.00 B) 0.122 C) 10.0 D) 1.22 E) 0.75
What is the pH of a buffer that consists of 0.45 M CH3COOH and 0.35 M CH3COONa? Ka = 1.8 x 10-5 So the answer is 4.64. However, I was under the impression that it is Ka * (base/acid). So wouldn't that be 1.8 x 10^-5 * (.35/.45)? Isn't the CH3COONa the base? Someone please explain. Thank you.
5. Please calculate the pH of a solution containing 0.40 M CH,COOH and 0.70 M CH3COONa (K, acetic acid = 1.8 X 10"): CH3COOH + H+ + CH3COO CH3COONa → CH3COO + Nat 6. The molar solubility of tin(ll) iodide is 1.28 x 10-2 mol/L. What is Ksp for this compound?
calculate the ph of a buffer solution that contains 1.5 M acetic acid (CH3COOH) and 0.3 M sodium acetate (CH3COONa) [Ka=1.8x10-5 for acetic acid]
QUESTION 8 Calculate the pH of a solution that is 0.384 M CH3COOH and 0.374 M CH3COONa. Ka of CH3COOH is 1.8 x 10". Enter your answer with two decimal places.
Calculate the pH of 1.0L of the buffer 2.00M CH3COONa/2.00M CH3COOH before and after the addition of 0.090 mol NaOH. The Ka of CH3COOH is 1.8x10^-5
7. Calculate the mass of sodium acetate (CH3COONa) that must be added to 1.00 L 0.450 M acetic acid (CH3COOH), Ka = 1.8 x 10 ) to form a pH = 5.00 buffer. Ka = 1.8 x 109.
What is the pH of a buffer that consists of 0.85 M CH3COOH and 0.35 M CH3COONa? Ka = 1.8 × 10–5 Select one: A. 4.64 B. 4.31 C. 5.52 D. 5.00 E. 4.85
Calculate the pH of a solution when 100.0 mL of a 0.100 M solution of acetic acid (CH3COOH), which has a Ka value of 1.8 × 10–5, is titrated with 110 mLs of a 0.10 M NaOH solution.