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The inner (plasma) membrane of E. coli is about 77% lipid by weight, with the remaining percentage due to protein (also by weight). How many molecules of membrane lipid are there for each molecule of protein? (Assume that the average protein has a molecular weight of 5.1 x 104 and the average lipid has a molecular weight of 7.8 x 102.) Report your answer to the nearest ones
Since Lipid makes up 77% so Total lipid would be
7.8 X 10^2 X 77 = 600.6 X 10^2 or 6.006 X 10^4
Similarlly Protein would be
assuming total 100 = 100-77 = 23
So Total amount of protein would be
5.1 X 10^4 X 23 = 117.3 X 10^4
Total mass of inner plasma membrane would be 117.3 X 10^4 + 6.006 X 10^4 = 123.306 X 10^4
Now calculate moles for each by formula
Number of Moles = GivenMassofCompound / MolarMassofCompound
For lipid it would be 600.6 X 10^2/7.8 X 10^2 = 77
Same for protein 117.3 X 10^4/5.1 X 10^4 = 23
So there are 77 moles of lipid and 23 moles of protein.
No calculate the number of molecules by formula
Number of Molecules= NumberOfMoles × 6.022×10^23 (Avogadro number)
So number of lipid molecules would be
77 × 6.022×10^23 = 463.54 X 10^23
So number of protein molecules would be
23 × 6.022×10^23 = 138.506×10^23
As per question the ration would be
No. of lipid molecules / No. of protein molecules
463.54 X 10^23 / 138.506×10^23 = 3.34
So there are average 3.34 or 3 molecules for each single molecule of protein in internal membrane of E.Coli
The inner (plasma) membrane of E. coli is about 77% lipid by weight, with the remaining...
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