- Questions & Answers
- Get Expert Help
- Get Coins
A highly regulated reaction in glycolysis involves the addition
of a second phosphate to fructose-6-phosphate, which could be be
Fructose-6-phostphate + Pi à Fructose-1,6-bisphosphate + H2O
The ∆Go’ for this reaction is +16.8 kJ/mol
In a muscle cell at 37 oC, assume the concentration of Fructose-6phosphate is 0.014 mM and the concentration of phosphate is 1 mM.
a. What would be the equilibrium concentration of fructose-1,6bisphosphate under these conditions?
b. What is Keq for this reaction?
First of all, we can calculate equilibrium constant (Keq) :
Part B) For the given reaction, equilibrium constant (keq) is calculated as,
ΔG° = - R T ln Keq
ΔG° = + 16.8 kJ/mol = + 16800 J/mol
T = 37 + 273 = 310 K
R = 8.314 J K-1 mol-1
ln Keq = - ΔG°/ RT
ln Keq = (-16800 J/mol)/ 8.314 J K-1mol-1 x 310 K
ln Keq = - 6.518
2.303 log Keq = - 6.518
log keq = - 2.83
keq = antilog (-2.83) = 1.48 x 10^-3
The equilibrium constant is related with the concentrations as,
Keq = [Products] / [Reactants ]
Keq = [Fructose-1,6-bisphosphate] / [Fructose-6-phosphate] [Phosphate]
1.48 x10^-3 = [Fructose-1,6-bisphosphate] / (0.014 mM x 1 mM)
[Fructose-1,6-bisphosphate] = 2.07 x 10^-5 mM
A highly regulated reaction in glycolysis involves the addition of a second phosphate to fructose-6-phosphate, which...
Question 4 Q . OH ATP OH POH ОН Fructose 6-phosphate Fructose 1.6-bisphosphate Figure 1. Reaction catalyzed by phosphofructokinase (PFK) during glycolysis Phosphofructokinase (PFK) is an enzyme that catalyzes the conversion of fructose 6- phosphate to fructose 1,6-bisphosphate during glycolysis, as represented in Figure 1. PFK can be allosterically inhibited by ATP at high concentrations. Which of the following is the benefit of regulating glycolysis by the concentration of ATP? Glycolysis proceeds when the intracellular concentration of ATP is low,...
QUESTION 19 In glycolysis, fructose 1,6-bisphosphate is converted to two products with a ∆G'° of 23.8 kJ/mol. Under what conditions encountered in a normal cell will the free-energy change (∆G) be negative, enabling the reaction to proceed spontaneously to the right? A. Under standard conditions, energy is released to drive the reaction to the right, B. the reaction will not go to the right spontaneously under any conditions because the ∆G'° is positive, C. the reaction will proceed spontaneously to...
Consider the given interconversion, which occurs in glycolysis. fructose 6-phosphate glucose 6-phosphate K1.97 What is AG for the reaction (K measured at 25 °C)? AG -1680.9 kJ/mol If the concentration of fructose 6-phosphate is adjusted to 1.4 M and that of glucose 6-phosphate is adjusted to 0.75 M, what is AG? AG =-4402.59 kJ/mol Which statements are consistent with the conditions at which AG is measured? The temperature is 273 K. The initial concentrations of reactant and product are 1...
The concentration of fructose 6-phosphate (F6P) and fructose 1, 6-biphosphate (F16BP), ATP, and ADP in muscle tissue were measured as 0.089, 0.012, 12.0, and 1.2 mM. For the reaction F6P(aq) + ATP(aq) rightarrow F16BP(aq) + ADP(aq) at 37 degree C, the standard Gibbs energy (at pFl=7) is -18.3 kJ/mol. Calculate the reaction Gibbs energy (kJ/mol) for the reaction in the muscle tissue environment. -71.2 -29.4 -7.3 +4.5 +11.2.
Please help me with number 7! If there is not enough information, please tell me what it needed so that I may add it. I do not need part d. All I I need is part a, b, and c. 7. In the cell, the synthesis of Fructose-1,6-bisphosphate is carried out by phosphofructokinase in the reaction: Fructose-6-phosphate + ATP → Fructose-1,6-bisphosphate + ADP a. What is the AGo' for this reaction if the AGo for ATP + H2O → ADP...
Question 1 (1 pt): In glycolysis, fructose 1,6-bisphosphate is converted to two products with a standard free-energy change (AG) of 23.8 kJ/mol. Under what conditions encountered in a normal cell will the free-energy change (AG) be negative, enabling the reaction to proceed spontaneously to the right? Under standard conditions, enough energy is released to drive the reaction to the right. a. b. The reaction will not go to the right under any conditions because AGo is positive. When there is...
Tautomerization of enolpyruvate to pyruvate occurs in step 10 of glycolysis. If DG°’ = -46 kJ/mol, what is the ratio of pyruvate to enolpyruvate at equilibrium? Steady-State Concentrations of Glycolytic Metabolites in Erythrocytes Metabolite mM Glucose 5.0 Glucose-6-phosphate 0.083 Fructose-6-phosphate 0.014 Fructose-1,6-bisphosphate 0.031 Dihydroxyacetone phosphate 0.14 Glyceraldehyde-3-phosphate 0.019 1,3-Bisphosphoglycerate 0.001 3-Phosphoglycerate 0.12 2-Phosphoglycerate 0.030 Phosphoenolpyruvate 0.023 Pyruvate 0.051 Lactate 2.9 ATP 1.85 ADP 0.14 Pi 1.0
Hexokinase catalyzes the following reaction in glycolysis: Glucose + ATP ← → glucose-6-phosphate + ADP The standard free-energy change for this reaction in the direction written is -16.7 kJ/mol. The concentrations of the related reaction components in the hepatocyte of a mammalian cell are: Glucose: 6 mM Glucose-6-phosphate: 0.074 mM ATP: 1.00 mM ADP: 0.25 mM What is the actual free-energy change for the reaction at body temperature (37 C)?
1. 2. 3. 4. Select all that apply. Identify the reaction(s) of glycolysis inhibited by ATP □ glyceraldehyde-3-phosphate → 1,3-bisphosphoglycerate phosphoenolpyruvate +pyruvate 3-phosphoglycerate ~2-phosphoglycerate 1) fructose-6-phosphate→ fructose-1,6-bisphosphate . glucose glucose-6-phosphate Select all that apply. Alcohol fermentation: consumes ATP as it produces ethanol. O produces carbon dioxide begins as pyruvate is decarboxylated to acetaldehyde in a reaction catalyzed by alcohol dehydrogenase m regenerates NAD requires the enzyme alcohol dehydrogenase, In the figure below, what is the reaction occurring at the location...
One reaction in glucose metabolism involves the cleavage of fructose-1, 6-bisphosphate to dihydroxyacetone phosphate and glvceraldehyde-3-phosphate. Enzymatically the reaction is catalyzed by aldolase. However, it can also be catalyzed by aqueous hydroxide. Propose the mechanism for the base-catalyzed reaction.