Calculate the equilibrium concentrations of H2, I2, and HI at
700 K if the initial concentrations are [H2] = 0.200 M and [I2] =
0.400 M. The equilibrium constant Kc for the reaction following
reaction is 57.0 at 700 K. (Show Work)
H2(g)+I2(g)<---
---->2HI(g)
We have,
Kc = [HI]^2/[H2][I2] = 57
ICE chart
H2 + I2 <===> 2HI
I 0.2 0.4 -
C -x -x -2x
E 0.2-x 0.4-x 2x
So,
57 = (2x)^2/(0.2-x)(0.4-x)
57x^2 - 34.2x + 4.56 = 4x^2
53x^2 - 34.2x + 4.56 = 0
x = 0.19 M
equilibrium concentration of,
[H2] = 0.2 - 0.19 = 0.01 M
[I2] = 0.4 - 0.19 = 0.21 M
[HI] = 2 x 0.19 = 0.38 M
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