The following sample observations were randomly selected: (Round the final answers to 4 decimal places.)
X: 16 14 9 17 12 11 20 18
Y: 14 21 1 13 11 16 14 15
a. Determine the 95% confidence interval for the mean predicted when X = 6.
b. Determine the 95% prediction interval for an individual predicted when X = 6.
The following sample observations were randomly selected: (Round the final answers to 4 decimal places.) X:...
The following sample observations were randomly selected. (Do not round the intermediate values. Negative amount should be indicated by a minus sign. Round your answers to 3 decimal places.) Y: a. Determine the 0.9 confidence interval for the mean predicted when x- 4 b. Determine the 0.9 prediction interval for an individual predicted whenx4
The following sample observations were randomly selected. (Round intermediate calculations and final answers to 2 decimal places.) 4 6 4 &Click here for the Excel Data File a. The regression equation is y- When X is 5 this gives y =
The following sample observations were randomly selected. (Round intermediate calculations and final answers to 2 decimal places.) X: y : 3 3 5 6 3 5 6 7 7 7 Click here for the Excel Data File + a. The regression equation is ý = b. When x is 6 this gives y =
The following sample observations were randomly selected. (Round your answers to 2 decimal places.) X: 4 5 3 6 10 Y: 10.8 12.6 8 14.4 19.6 a. The regression equation is Yˆ Y^ = + X b. When X is 7 this gives Yˆ Y^ =
Given are five observations for two variables, x and y. (Round your answers to two decimal places.) xi 3 12 6 20 14 yi 55 40 55 10 15 (a) Estimate the standard deviation of ŷ* when x = 11. (b) Develop a 95% confidence interval for the expected value of y when x = 11. to (c) Estimate the standard deviation of an individual value of y when x = 11. (d) Develop a 95% prediction interval for y...
1. A sample of 36 observations is selected from a normal population. The sample mean is 21 , and the population standards deviation is 5 . Conduct a test of hypothesis using the 0.05 significance level. Null hypothesis =20 . Alternate = ?2. A sample of 81 observations is taken from normal population with a standard deviation of 5 . The sample mean is 40 . Determine the 95 %confidence interval for the population.3. Given the following sample observations which...
Exercise 2: The following sample observations were randomly selected. X Y 5 13 3 15 6 7 3 12 4 13 4 11 6 9 8 5 a. Insert the trendline equation. b. Determine the coefficient of correlation and the coefficient of determination.
Given are five observations for two variables, x and y. y3 7 6 11 14 Round your answers to two decimal places. a. Using the following equation: Estimate the standard deviation of ý" when x 4. b. Using the following expression: Develop a 95% confidence interval for the expected value of y when x-4. to c. Using the following equation: 1 nY Estimate the standard deviation of an individual value of y when x -4. d. Using the following expression...
A sample of 23 observations is selected from a normal population where the population standard deviation is 28. The sample mean is 71. a. Determine the standard error of the mean. (Round the final answer to 3 decimal places.) The standard error of the mean is . b. Determine the 95% confidence interval for the population mean. (Round the z-value to 2 decimal places. Round the final answers to 3 decimal places.) The 95% confidence interval for the population mean is...
Round your answers to two decimal places. a. Using the following equation:\(S_{\hat{y}},=s \sqrt{\frac{1}{n}+\frac{\left(x^{*}-\bar{x}\right)^{2}}{\sum\left(x_{i}-\bar{x}\right)^{2}}}\) Estimate the standard deviation of \(\hat{y}^{*}\) when \(x=3 .\)b. Using the following expression:\(\hat{y} * \pm t_{\alpha / 2} s_{\hat{y}}\)Develop a \(95 \%\) confidence interval for the expected value of \(y\) when \(x=3\). toc. Using the following equation:$$ s_{\text {pred }}=s \sqrt{1+\frac{1}{n}+\frac{\left(x^{*}-\bar{x}\right)^{2}}{\sum\left(x_{i}-\bar{x}\right)^{2}}} $$Estimate the standard deviation of an individual value of \(y\) when \(x=3\).d. Using the following expression:\(\hat{y}^{*} \pm t_{\alpha / 2} s_{\text {pred }}\)Develop a \(95 \%\) prediction...