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In the CS amplifier shown in the figure above, Rsig = 20 kΩ amplifier input resistance...

In the CS amplifier shown in the figure above, Rsig = 20 kΩ amplifier input resistance Rin = 80 kΩ, Cgs=2pF, Cgd= 0.5pF, gm=2mA/V, ro= 80 kΩ , RD = 5 kΩ, and RL = 10 kΩ. (π = 3.14)

a) Determine high frequency cut-off fH. (Use Miller Approximation. Use . as the decimal point. Answer in MHz; for 7.89MHz write 7.89 only.)

VOD RD V RIS R CS V Ro In the CS amplifier shown in the figure above. Rsig = 20 kN amplifier input resistance Rin = 80 kN. Cg

VOD RD V RIS R CS V Ro In the CS amplifier shown in the figure above. Rsig = 20 kN amplifier input resistance Rin = 80 kN. Cgs=2pF. Cgd= 0.5pF. &m=2mA/V.1.=80k, Rp = 5 k1, and R1 = 10 k1. (1 = 3.14) a) Determine high frequency cut-off fH (Use Miller Approximation. Use . as the decimal point. Answer in MHz; for 7.89MHz write 7.89 only.)
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1 Solution VOD ERD CC 카 V con Reig 3RL 80k RG ² Cs Y TT -Vse Ro=5kn No=80kn R₂ =loke Ge Cgd = o.spf gr= amaly Small signal ac- 86.048 X10 H3 Con=0.5pf (1-10) (gd= 0.5pf -0.578 PT Rotho - Rtho= rollRoltre 80k||5k|llok 53.26.2 12 Ho 91T X3.2x10x0.598 X

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