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need it ASAP thanks The exercise involving data in this and subsequent sections were designed to...

The exercise involving data in this and subsequent sections were designed to be solved using Excel. The following estimated r

- Select your answer At a = .05, what is your condusion? - Select your answer - C. Compute the t test statistic for the signi

need it ASAP thanks

The exercise involving data in this and subsequent sections were designed to be solved using Excel. The following estimated regression equation is based on 10 observations was presented. y = 29.1270 +0.59061 +0.49802, Here SST = 6,532.000, SSR = 6,078.625, 86, = 0.0775, and 8h = 0.0670. a. Compute MSR and MSE (to 3 decimals). MSR MSE b. Compute the F test statistic (to 2 decimals). Use F table. What is the p-value? - Select your answer - At a = .05, what is your conclusion? - Select your answer - c. Compute the t test statistic for the significance of B1 (to 2 decimals). Use t table. The p-value is - Select your answer At a = .05, what is your conclusion?
- Select your answer At a = .05, what is your condusion? - Select your answer - C. Compute the t test statistic for the significance of (to 2 decimals). Use t table. The p-value is - Select your answer At a = .05, what is your conclusion? - Select your answer - d. Compute the t test statistic for the significance of B2 (to 2 decimals). Use t table. The p-value is - Select your answer At .05, what is your conclusion? - Select your answer Olen ke Check My Exercise 15 19
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(a)

There are 2 predictor variables so degree of freedom of regression is

df_{reg}=2

There are total 10 observations so degree of freedom of error is

df_{res}=10-2-1=7

MSR=\frac{SSR}{df_{reg}}=3039.313

MSE=\frac{SST-SSR}{df_{res}}=64.768

(B)

The F test statistics is

F=\frac{MSR}{MSE}=46.93

The p-value is

p-value < 0.001

Since p-value is less than level of significance so we reject the null hypothesis.

(C)

Here we have b = 0.5906, n = 10, sb, = 0.0775 Hypotheses are: Ho:B2 = 0 H :B 0 Level of significance: a =0.05 Test is two tai

Answers:

t = 7.62, p-value < 0.001, Reject H0

(d)

Here we have b = 0.498, n = 10, sb, = 0.067 Hypotheses are: H:B2 = 0 H.:B270 Level of significance: a =0.05 Test is two taile

Answers:

t = 7.43, p-value < 0.001, Reject H0

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