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12b. A 100-L beaker contains 10 kg of salt. Pure water is added at the constant...


12b. A 100-L beaker contains 10 kg of salt. Pure water is added at the constant rate of 5 L/min with complete mixing and draw
12b. A 100-L beaker contains 10 kg of salt. Pure water is added at the constant rate of 5 L/min with complete mixing and drawn off at the same rate. How much salt is in the beaker after 1 hour? [Let y(t) be the amount of salt in the beaker at any timet dV (Hint: .-C . Please show the values of the constants at each step of your solution) di
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Q: if y(4) be the amount of salt in the beaker at any time I then for mixing problem dy = Rate in - Rate out 6 at The water eOR I min - 400 5 Kg Imin Rob out = 5.kg Imio = the kg limim from 20 dy = - dt I s I dx = lnx Integrate con both sides Sody =10=Cl e = 1 *.0=1 so amount of salt at time ! y = lo è t/20 o t = there = Go min. ŷ = lo 5-60/20 Y = 10 8 = lox 0.0497870684

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