From gas laws
b)
we know PV=nRT
R = 0.082057 L-atm /mol K
putting P= 1 atm and T= 303 K
we get
n= 0.0201 moles
c)
now P = 0.95 atm
T =299 K
we get n= 0.0193
d)
We from from kinetic theory of gases
K.E= 3/2nRT
where K.E is kinetic energy
so K.E = 1.5 X 8.314 X 303
= 3778.713 J/mol
e)
for process under constant volume
molar heat capacity = Cv
given the gas is diatomic so Cv =5/2 R
now Q= nCv
Q=7690.45 J
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