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The formation constant of M(CN)61 is 2.50 x 107, where M is a generic metal. A 0.130 mole quantity of M(NO3) is added to a l
The generic metal A forms an insoluble salt AB(s) and a complex ACs(aq). The equilibrium concentrations in a solution of ACs
can someone please help me answer these, for some reason theh are both wrong and i cant get them right, will rate you good if you can help get both correct answers! thanks
The formation constant of M(CN)61 is 2.50 x 10'7, where M is a generic metal. A 0.130 mole quantity of M(NO3) is added to a liter of 1.180 M NaCN solution. What is the concentration of M2+ ions at equilibrium? [M ] = 4.6 x10-19
The generic metal A forms an insoluble salt AB(s) and a complex ACs(aq). The equilibrium concentrations in a solution of ACs were found to be [A] = 0.100 M. [C] = 0.0170 M, and [ACs) = 0.100 M. Determine the formation constant, Ki, of ACs. Ki= 7.043 x108 The solubility of AB(s) in a 1.000 M solution of C(aq) is found to be 0.153 M. What is the Ksp of AB? Kp = 3.27 x10-7
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Answer #1

Sol M (NO3)₂ + NaCN [M(CN) 6] as M(NO3)₂ & NaCN both are 100% ionizable So, we will get t2 & N ions in solution, along with N

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