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2. For the pin-jointed truss shown in Figure Q2.1 applied at node 4. The Young's modulus E(GPa) is the same for...


2. For the pin-jointed truss shown in Figure Q2.1 applied at node 4. The Youngs modulus E(GPa) is the same for the three tru
2. For the pin-jointed truss shown in Figure Q2.1 applied at node 4. The Young's modulus E(GPa) is the same for the three truss vertical downward force P(kN) is a members. The cross sectional area of each of the truss members is indicated below and expressed in terms of a constant A. By using the stiffness method: (a) Compute the reduced stiffness matrix Kg [5 marks [10 marks (b) Calculate the global displacements of node 4 in terms of P, A and E (c) Calculate the axial forces in each of the truss members stating whether it is in tension or in compression in terms of P. [10 marks] 2 P (kN) (&ffz2e) G A 10 mm2 A (0428) A 2A-10 mm2 A, A 10 mm 60° 3 3 4m Figure Q2.1
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P us m-3 2 2 Kese /_c CS s2 csS 3 CS AE -c -cs GO 2 C cs -s C S Foxes in members Pere A E 47 -5. 21 co-ordinates 2 joints 3 L1 4 m A1 10000 MM2 LET A-1 LET A 1 V 5.65 m A2 4 1 C 6.928 L2 20000 MM2 LET E-1 E 1 m 5 2 C 2.9287 5 6 7 8 30 K3 0,00125 0.25 0.433 0.25 -0.433 0,00031 0,00054 -0.0003 -0.0005 0.433 0.74996 0.00054 0,00094 -0.0005 AE -0.43H F K X 4 3 6 8 O0 25 UADUZD 2 3 00c021 ncoos4 0.0002 0.0005. 00954-0E9094- -0.0003 -0.0005 .0005 00005 0.00459 0.00232 -0b0089 INTERNAL FORCES 90 1 -1 U7 91 MEMBER 1 0.0025 -1 1 X 1 X U8 92 U1 93 U2 94 95 0 X 96 0.0025 1 -1 327.217 P 97 -648.19 P 0112 113 force in member 2 114 327.217 p 115 0.00354 -0.708 -0.708 0.70796 0.70796 X -648.19 p 116 0 p 117 0 p 118 119 120 327

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