# How do you solve 5(-3x-2)-(x-3) = -4(4x+5)+13?

How do you solve 5(-3x-2)-(x-3) = -4(4x+5)+13?

Answer 1

$x$ has any value.

#### Explanation:

Remove the brackets first using the distributive law.

$5 \left(- 3 x - 2\right) - \left(x - 3\right) = - 4 \left(4 x + 5\right) + 13$

$- 15 x - 10 - x + 3 = - 16 x - 20 + 13$

$- 16 x - 7 = - 16 x - 7 \text{ } \leftarrow$ both sides are identical.

$- 16 x + 16 x = - 7 + 7 \text{ } \leftarrow$ this leads to

$0 = 0 \text{ } \leftarrow$ true, but there is no $x$ to solve for.

This is an identity which means that it will be true for any value of $x$

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