#1/4. x^(2/3)/y^(7/4)#
Given,#{3y^(1/4)}/[4x^(-2/3)xxy^(3/2)xx3xxy^(1/2)]#
#rArr 3/(4xx3). y^(1/4) y^(-3/2)y^(-1/2)x^(2/3)#
#rArr 1/4. y^(1/4-3/2-1/2)x^(2/3)#
#rArr 1/4. y^(-7/4)x^(2/3)#
#rArr 1/4. x^(2/3)/y^(7/4)#
How do you simplify #(3y^(1/4))/(4x^(-2/3)y^(3/2)*3y^(1/2))#?
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