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How do you divide #(-3x^3-23x^2-4x+1)/(x-4) #?

How do you divide #(-3x^3-23x^2-4x+1)/(x-4) #?
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Answer #1

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#color(green)(=>"Quotient " -3x^2 - 35x - 144, " Remainder " -575/ (x-4) #

Explanation:

#(3x^3 - 23x^2 - 4x + 1 ) / (x - 4)#

#color(white)(aaa) - - - - - - - - - - - - - #

#4 color(white)(aa) | color(white)(aa) -3 color(white)(aaa) -23 color(white)(aaaa) -4 color(white)(aaaa) + 1#

#color(white)(aaa) | color(white)(aaaa) darr color(white)(aa) -12 color(white)(aa)-140 color(white)(aa) -576#

#color(white)(aaa)|- - - - - - - - - - - - - #

#color(white)(aaa)| color(white)(aa) -3 color(white)(aaa) -35 color(white)(aa) -144 color(white)(aa) -575#

#color(green)(=>"Quotient " -3x^2 - 35x - 144, " Remainder " -575/ (x-4) #

answered by: sankarankalyanam
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