# How do you solve -x ^ { 2} - 4x - 3= 3x + 4?

How do you solve -x ^ { 2} - 4x - 3= 3x + 4?

Answer 1

$x = \frac{- 7 + \sqrt{21}}{2}$ or $x = \frac{- 7 - \sqrt{21}}{2}$

#### Explanation:

Given
$\textcolor{w h i t e}{\text{XXX}} - {x}^{2} - 4 x - 3 = 3 x + 4$

After re-arranging into standard form:
$\textcolor{w h i t e}{\text{XXX}} {x}^{2} + 7 x + 4 = 0$

$\textcolor{w h i t e}{\text{XXX}} x = \frac{- 7 \pm \sqrt{{7}^{2} - 4 \cdot 1 \cdot 7}}{2 \cdot 1} = \frac{- 7 \pm \sqrt{21}}{2}$

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