Atomic weight can be calculated by using following formula
atomic weight= massa × fracta + massb × fracb+ massc × fracc
Where, a,b and c are used for first,second and third isotopes.
We need to convert percentage into fractions by dividing each percentage term by 100.
Now,
Atomoic weight = 27.977 × 0.9223 + 28.976 × 0.04679 + 29.974 × 0.031
= 25.8031871 + 1.35578704 + 0.929194
= 28.0881681
= 28.09 amu
Therefore, first option is the right option.
Naturally occurring element X exists in three isotopic forms X-28 (27.977 amu 02 23% abundance) X-29...
References Naturally occurring element X exists in three isotopic forms: X-28 (27.970 amu, 92.21% abundance), X-29 (28.976 amu, 4.70% abundance), and X-30 (29.974 amu, 3.09% abundance). Calculate the atomic weight of X A. 25.79 amu B. 28.08 amu C. 86.92 amu D. 35.28 amu E. 29.08 amu Submit Answer Try Another Version 1 item attempt remaining
QUESTION 1 The formula mass of ammonium phosphite, (NH 4) 3PO 3, is a. 153.11 amu O b. 125.01 amu c. 97.01 amu d. 133.09 amu QUESTION 2 Naturally occurring element X exists in three isotopic forms: X-28 (27.977 amu, 92.23% abundance), X-29 (28.976 amu, 4.67% abundance), and X-30 (29.974 amu, 3.10% abundance). Calculate the atomic weight of X. a. 27.16 amu b.28.97 amu O c. 86.93 amu d. 48.63 amu e. 28.09 amu QUESTION 3 Balance the following equation...
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An element has three naturally occurring isotopes with the following masses and abundances (in parenthesis): 27.977 amu (0.9222); 28.974 amu (0.0469); 29.974 amu (0.0310). Calculate the atomic weight of the element. a. 28.09 amu b. 66.94 amu c. 86.93 amu d. 29.98 amu
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