Given:
Gof(SO2(g)) = -300.2 KJ/mol
Gof(O2(g)) = 0.0 KJ/mol
Gof(SO3(g)) = -371.1 KJ/mol
Balanced chemical equation is:
2 SO2(g) + O2(g) ---> 2 SO3(g)
ΔGo rxn = 2*Gof(SO3(g)) - 2*Gof( SO2(g)) - 1*Gof(O2(g))
ΔGo rxn = 2*(-371.1) - 2*(-300.2) - 1*(0.0)
ΔGo rxn = -141.8 KJ
We have:
T = 298.15 K
ΔGo = -141.8 KJ/mol
ΔGo = -141800 J/mol
use:
ΔGo = -R*T*ln Kc
-141800 = - 8.314*298.15* ln(Kc)
ln Kc = 57.2047
Kc = 6.977*10^24
Answer: 6.98*10^24
Calculate the equilibrium constant from the standard free energy change. Using standard thermodynamic data (linked), calculate...
*** ** -305.01 -183.9 151.1 NH4NO3 (aq) -339.9 -190.6 259.8 AHºf (kJ/mol) AG°f (kJ/mol) Sº (/mol K) 0 205.1 Oxygen 02 (g) O(g) 03 (g) 249.2 231.7 161.1 142.7 163.2 238.9 Phosphorus AH° (kJ/mol) AG°f(kJ/mol) sº (/mol K) Nitrogen AH°(kJ/mol) AG°f(kJ/mol) s° /mol K) N2 (8) 0 191.6 N (g) 472.7 455.6 153.3 NH3 (g) -46.1 -16.5 192.5 NH3 (aq) -80.0 -27.0 111.0 132.0 -79.0 113.0 90.3 86.6 210.8 51.7 66.1 261.8 NH4+ (aq) NO (g) NOCI (9) NO2 (g)...
Use standard thermodynamic data (in the Chemistry References) to calculate AG at 298.15 K for the following reaction, assuming that all gases have a pressure of 10.88 mm Hg. 2NO(g) + O2(g)—>2NO2(g) AG= kJ/mol Nitrogen AHºf (kJ/mol) AG°f (kJ/mol) sº (J/mol K) N2(g) 191.6 N(9) 472.7 455.6 153.3 NH3(9) -46.1 -16.5 192.5 NH3(aq) -80.0 -27.0 111.0 NH4+ (aq) -132.0 -79.0 113.0 NO(9) 90.3 86.6 210.8 NOCI(g) 51.7 66.1 261.8 NO2(9) 33.2 240.1 51.3 104.2 N2O(9) 82.1 219.9 N204(9) 9.2 97.9...
Use the data from this table of thermodynamic properties to calculate the values of ASixn for each reaction at 25 °C. 4NH,(g) + 70,(9) — 4NO2(g) + 6H2O(g) AS:n = J/mol K N,() + 0,(g) 2 NO(g) J/mol K Asian = MISU415) -1065.25 N2(9) N2H4(0) 50.6 N20(9) 81.6 N204(9) 11.1 N205(9) 13.3 NH3(9) -45.9 NH3(aq) -80.29 NH,+(aq) -133.3 NH4CI(S) -314.4 NH4NO3(s) -365.6 (NH2)2CO(s) -333.1 Na(s) Na+(aq) -240.3 Na2CO3(S) -1130.7 NaCl(s) -411.2 NaF(s) -576.6 NaBr(s) -361.1 Nal(s) -287.8 NaNO3(s) -467.9 NaOH(s)...
For each part below, use the data below to calculate AG at 205 K for each of the following reactions. Then use the data in the chart to determine whether each reaction is spontaneous at 205 K. H2S(g) O2(g) H20(g) SO2(g) SO3(g) H2SO4 -690.0 S(g) H20(1) 33.01 0 -228.6 300.1 371.1 205.6 205.0 188.7 248.2 256.8 156.9 167.8 70.0 20.17 0 241.8 296.8 395.7 814.0 277.2 285.8 236.7 237.2 2S02(g)+02(2)>2S0,(g) ΔG205 -151.8 kJ Choose one: Spontaneous Nonspontaneous SO,( H20)HS40) AG205-...
Calculate the equilibrium constant from the standard free energy change. Using standard thermodynamic data (linked), calculate the equilibrium constant at 298.15 K for the following reaction. N2(g) + 3H2(9) 2NH3(g)
Consider the reaction 2 CO2(g) +5 H2(e) C H2(e) + 4H2O(g) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K ANSWER: Submit Answer Retry Entire Group more group attempts remaining AH,(kJ/mol) AG® (kJ/mol) Sº (J/mol K) -238.7 -116.0 126.8 219.0 -363.0 249.0 135.1 -166.3 -110.0 -351.0 125.0 209.2 68.2 - 129.0 202.0 226.7 200.9 52.3 - 166.0 -53.0 -277.7 219.6 250.0 242.0 160.7 -13.0 -235.1 282.7 Carbon CH3OH (1) H2CO...
Calculate the equilibrium constant from the standard free energy change. Using standard thermodynamic data (linked), calculate the equilibrium constant at 298.15 K for the following reaction. H2(g) + Cl2(g)—>2HCI(g) K=
help with this please
Ca(OH)2(aq) + 2 HCl(aq) +CaCl2(8) + 2 H2O(1) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K ANSWER: N2(g) + O2(g) +2NO(g) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K ANSWER: 2CO(g) + O2(g) +2002(9) - der e en manos de 20, ali ne more than one so mi dicogna undan Using standard thermodynamic data...
6C02(g) + 6H2O(1)— C6H1206+602(g) Using standard thermodynamic data at 298K, calculate the free energy change when 1.92 moles of CO2(g) react at standard conditions. AGºrxn = Carbon AH°F (kJ/mol) AG°f (kJ/mol) Sº (J/mol K) 5.7 2.4 C(s, graphite) C(s, diamond) C(9) CC14 (1) 1.9 716.7 2.9 671.3 158.1 -135.4 -65.2 216.4 CCl4(9) -102.9 -60.6 309.9 CHCl3(1) -134.5 -73.7 201.7 CHCl3(9) -103.1 -70.3 295.7 CH4(9) -74.8 -50.7 186.3 CH3OH(g) -200.7 -162.0 239.8 CH3OH(1) -238.7 -166.3 126.8 H2CO(g) -116.0 219.0 HCOOH(g) -363.0...
(References TUTOR Entropy Change: Predict Sign, Calculate from Standard Entropy Values Consider the reaction CO(g) + H20(1)—CO2(g) + H2(g) Based upon the stoichiometry of the reaction the sign of AS rxn should be Using standard thermodynamic data, calculate AS rxn at 25°C. positive negative ASDXD J/K mol Submit Show Approach Show Tutor Steps Submit Answer Retry Entire Group 9 more group attempts remaining Selected Thermodynamic Data at 298.15 Kelvin Aluminum, Barium, Beryllium, Bromine, Cadmium, Calcium, Carbon, Chlorine, Chromium, Copper, Fluorine,...