Given,
vi = 4 i + 1 j ; t = 19 s ; v = 15 i - 3 j
a)we know that
a = (v2 - v1)/t = (v - vi)/t
a = (15 i - 3j - 4 i - 1 j)/19 = 0.579 i - 0.211 j
ax = 0.579 m/s^2
ay = -0.211 m/s^2
b)theta = tan^-1 (-0.211/0.579) = -20.02
theta = 360 - 20.02 = 340 deg
Hence, theta = 340 deg
c)we know that
s = s0 + ut + 1/2 at^2
s = 16 i - 4.2 j + (4 i + 1 j) 28 + 1/2 x 28^2 (0.579 i -0.211 j)
s = 16 i - 4.2 j + 112 i + 28 j + 227 i - 82.71 j
s = 355 i - 58.91 j
x = 355 i
y = -58.91 j
theta = tan^-1(-58.91/355) = -9.4
theta = -9.4 + 360 = 350.6 deg
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