Question

Combustion Analysis Copper(II) oxide (CuO) pellets UU Excess Oxygen in oxygen out Furnace Sodium hydroxide (traps CO) Drying agent (traps H2O) Sample dish х СО, + у H,0 С, н, о, + nO, 2 o Start with 58 g of compound that has only C, H, and O in it After reaction find you have 132 g of CO2 and 54 g of H20 Determine mass % of each element and empirical formula

Answer 1

By combustion analysis with the known amount of carbon dioxide and water released during reaction.we can find out the empirical formula of the comound.
Mas gucm Comteund Cmp ound idd 132 9 usht moli No Maa'r mars Carbon 132-9 3 Mates 7 3md es mutes 3 mat o 6 mote oM चादूछ im 6 mote hydoa-6mdx 1glmd-6 3 motu o Cautbon C in Hasr Mau H Mas o1 givcm Aample -(Mas o1 C+Mas 58-(3t6) 58 - १2- 2 |16 । mod of Narw 16 9 Notes Mau / Ma C- Naw o Carbon led 364xlD G3.06. Mam HE lo.31/ 581 16 1 Xloo 58
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Mates Mte ydocn 4on-1 Hemc formula s Canbon Nde