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Question 1
1. Using an equation like equation 3, derive the expression for k given in equation 4. 2. What solvent mixture are you using
Equation 3. naltooe [R-Clo 2.303 log k= 0.693/t12 kt12 2.303 log 2 R-C]o- 0.5[R-CIo Similarly, we can also solve for k in ter
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o Equation Equation 3 2-303 lng CR-C1). [R-C1]. -0.5 [R-C1]. skity > Ke 2.303 ty veg CR-ci] [R-C17. - 0.5[R-ci). ty means tim2.303 k= 2: 80 log in 1 - 0:1) 8-ci Ka * 2o long losa) Kedai (0.04 $157) k = o.105379 ० k: 0. 1054 the K = 0.2054/74 = 0.4

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