Question

Question 4 Use MATLAB's built in function fminbnd() to solve for the optimum of the following one-dimensional functions: Not yet answered 822 What is the x value at the minimum of f(x 28x, using an initial bracket of 0.5< < 2.5? Marked out of 4.00 What is f(rmin)? Flag question value at the maximum of f(x) What is the 5), using an initial bracket of 8< < 18? What is f(amax?

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Answer 1

ANSWERS-

1. F(xmin)= -24.5

2. F(xmax)= 43.597

MATLAB CODE-------------------#####

disp('Minimum of function')
Fun=@(x) (8*x^2-28*x)
[xmin,Fxmin]=fminbnd(Fun,0.5,2.5)

fprintf('\nTo find maximum of function')
f=@(x1) (-(5*x-((x-5)^2)/3))
[x1,fval1]=fminbnd(f,8,18);

xmax=11.820
Fxmax=5*d-0.3333*(d-5)*(d-5)

RESULTS-----------------------------------------------------######

Minimum of function
Fun =

@(x) (8 * x ^ 2 - 28 * x)

xmin =  1.7500
Fxmin = -24.500

To find maximum of functionf =

@(x1) (-(5 * x - ((x - 5) ^ 2) / 3))

xmax =  11.820
Fxmax =  43.597