Question

crystal was analyzed with x-rays having 1.50 Å wavelength. A reflection was produced at an angle of θ = 23.1°. Assuming n = 1, what is the distance between the layers of atoms in the crystal?

A. 7.65 Å

B. 3.82 Å

C. 0.523 Å

D. 0.815 Å

E. 1.91 Å

Answer 1

By Bragg equation

n$\lambda$ = 2 d sin$\theta$

So, distance between two layers (d) =

nd 2 Sino

Given,

$\theta$ = 23.1⁰

n = 1

Wavelength ($\lambda$) = 1.50 A^o .

So, d =
_{1 x 1.50 2.Sin (23.10}

Or, d =

1 1.50 2 x 0.392

Or, d = 1.91 A^o .

So, correct option is E) 1.91 A^o .