Question

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7. -/1 points SerPOP4 1.P.067. My Notes The helicopter view in the figure shows two people pulling on a stubborn mule. Let the magnitude of F2 = 88.0 N and the angle at which F1 pulls be o = 70.00 75.0 VA (a) Find the single force that is equivalent to the two forces shown. The forces are measured in units of newtons (symbolized N). ONÎ + CNÎ (b) Find the force that a third person would have to exert on the mule to make the resultant force equal to zero. CNÎ + CNÍ

Answer 1

The forces are

$F_1= 120. (\hat x \cos (70. {}^{\circ})+\hat y \sin (70. {}^{\circ}))=(41.042\hat x + 112.76\hat y)N$

$F_2= 88. (-\hat x \cos (75. {}^{\circ})+\hat y \sin (75. {}^{\circ}))=(-22.78\hat x + 85.00\hat y)N$

The total force is

$F_1+F_2= (18.27\hat x+ 197.77\hat y)N=(18.27\,\hat i+ 197.77\,\hat j)N$

The third force should be opposite of F1+F2

$F_3 = -(F_1+F_2)= -18.27\,\hat i- 197.77\,\hat j\,\,N$