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The formula for range of a projectile which is projected with an initial speed u making angle with horizontal is given as,
R = u2 sin 2/g
Where g is the free fall acceleration. For maximum range or horizontal distance, = 45o . So, considering the astronaut as a projectile, we have,
20 = 32 sin 2*45o/g => g = 9*sin 90o/20
Thus, free fall acceleration, g = 9/20 = 0.45 m/s2
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An astronaut on a strange planet finds that she can jump a maximum horizontal distance of 16.0 m if her initial speed is 3.80 m/s. What is the free-fall acceleration on the planet? (Ignore air resistance.)
An astronaut on a strange planet finds that she can jump a maximum horizontal distance of 17.0 m if her initial speed is 3.80 m/s. What is the free-fall acceleration on the planet? (Ignore air resistance.) m/s
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