Question

The formula for range of a projectile which is projected with an initial speed u making angle $\dpi{150} \theta$ with horizontal is given as,

R = u2 sin 2$\dpi{150} \theta$/g

Where g is the free fall acceleration. For maximum range or horizontal distance, $\dpi{150} \theta$ = 45o . So, considering the astronaut as a projectile, we have,

20 = 32 sin 2*45o/g => g = 9*sin 90o/20

Thus, free fall acceleration, g = 9/20 = 0.45 m/s2

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