Problem 6 A current i runs counterclockwise along the perimeter of an equilateral triangle whose sides...
The effects due to the interaction of a current-carrying loop with a magnetic field have many applications, some as common as the electric motor. This problem illustrates the basic principles of this interaction.Consider a current I that flows in a plane rectangular current loop with height a = 4.00cm and horizontal sides b = 2.00cm. The loop is placed into a uniform magnetic field B? in such a way that the sides of length a are perpendicular to B? and there is an...
The current in the triangular wire loop is I = 5.0 A, as shown in the figure. The loop is in a flat magnetic field B = (3.0T) (a) Calculate the magnetic moment of the current loop and, with it, calculate the torque affecting on the loop In what direction does this torque tend to turn the loop? (b) Calculate the magnetic forces affecting on the sides of the triangle and, with their help, calculate the magnetic torque. (Can you...
only need part B answered please.
A one-turn current loop, in the shape of an equilateral triangle with sides a, lie in the x-y plane and moves with velocity v in the +x direction. (Assume that some external force that is not shown in the figure keeps the velocity constant.) The loop has a net resistance of R. It passes through a region of constant, spatially uniform magnetic field B that points in the -z direction (into the screen) and...
The picture shows a rectangular current-carrying loop in a uniform magnetic field that is directed right. The loop is free to rotate about the axis shown as the dashed line in the top view. (a) Select all the correct statements about this situation from the list below. As seen from the side view, the initial net torque on the loop is clockwise As seen from the side view, the initial net torque on the loop is counterclockwise As seen in the top view, the...
Please solve this problem immidiately Thank you
A triangle loop of wire shown in figure carries a current l = 3.0 A in the direction shown. The loop is in a uniform magnetic field that has magnitude B = 2.0 T with the same direction as the current in side PQ of the loop. 9 pts) a) Find the magnitude and direction of the magnetic force on each side of the triangle. (5 pts) b) What is the net magnetic...
top view side view The picture shows a rectangular current-carrying loop in a uniform magnetic field that is directed right. The loop is free to rotate about the axis shown as the dashed line in the top view. (a) Select all the correct statements about this situation from the list below As seen from the side view, the initial net torque on the loop is clockwise As seen from the side view, the initial net torque on the loop is...
A wire loop with current I is placed in a uniform magnetic field. Which statement(s) are true about the wire loop? The net force is zero, but the net torque is not. There are no forces exerted on the current loop. The net force is zero. The loop will rotate.
Chapter 21, Problem 46 GO The triangular coil of wire in the drawing is free to rotate about an axis that is attached along side AC. The current in the loop is 4.31 A, and the magnetic field (parallel to the plane of the loop and side AB) is B = 1.9 T. (a) What is the magnetic moment of the loop, and (b) what is the magnitude of the net torque exerted on the loop by the magnetic field?...
The triangular loop of wire shown in the drawing carries a current of I = 5.30 A. A uniform magnetic field is directed parallel to side AB of the triangle and has a magnitude of 1.80 T. (a) Find the magnitude and direction of the magnetic force exerted on each side of the triangle. (b) Determine the magnitude of the net force exerted on the triangle. KNOW WANT STRATEGY
4. In this problem and in the next, you will calculate the torque on a current loop. In lecture we analysed the torque on a rectangle, while in the recitation you analysed a circle. Here you will consider a current loop in the shape of an equilateral triangle, where each side has a length a. In this problem you will evaluate the torque by directly finding the torque on each side due to a magnetic field B = Bý. Please...