1 mole of acetic acid react with 1 mole of isopentyl alcohol to from product
here isopentyl alcohol is limiting reagent so
mole of product form will be = 2.92 mmoles
molar mass of isopentyl acetate ( product) = 130.18 g/mol
theroretical yield = 2.92 * 130.18 = 380 mg
theoretical yield = 0.38 g
table
compound MW equivalent mmol g mL
acetic acid 60.05 g/mol 5.84/2.92 = 2 5.84 0.351
isopentyl alcohol 88.148 g/mol 2.92/2.92 = 1 2.92 0.257
sulfuric acid (18M) 0.288/2.92=0.1 0.288 0.016
amount of equivalent is calculated with respect to the stoichiometric amount of limiting reagent.
Complete the table 2. Complete the following table: Compound MW equivalents mmo mL density Acetic acid,...
Complete the table for the reaction
Compound
MW
Equivalents
mmol
g
density
mL
Acetic Acid (glacial)
60.05
1.049
Isopentyl alcohol
88.15
0.810
18 M sulfuric acid
XXX
XXX
XXX
XXX
0.022
Low Hond Is Lord +
Compound MW equivalents mmol g density mL Sulfuric Acid (18 M) XXX XXX XXX 1.711 methyl benzoate 0.820 sulfuric acid (18 M) XXX XXX XXX 0.546 nitric acid XXX XXX XXX 0.560 1. Complete the following table: (hint keep track of your units) 2. What is the theoretical yield for this reaction?
1. Complete the following table: (Hint-Keep track of your units) equivalents mmol density mL Compound sulfuric acid (18M) MW XXX XXX XXX 0.840 2.96 1.04 0.302 benzaldehyde sulfuric acid (18M) nitric acid (15.9M) XXX XXX XXX 0.280 XXX XXX XXX 0.372 2. What is the theoretical yield for this reaction (nitration of benzaldehyde)?
Prelab Questions. Complete the following table: (hint keep track of your units) MW equivalents mmol ml density XXX 0.920 XXX XXX Compound sulfuric acid (18M) methyl benzoate sulfuric acid 1.088 0.440 XXX XXX XXX 0.460 (18M) XXX 0.440 XXX XXX nitric acid (15.9M) 2. What is the theoretical yield for this reaction? 3. Why is an ice bath employed in the nitration of methyl benzoate? (hint: look at the energy diagram shown on pg 1 of the experiment)
i need help with the rest of the question
1a. Volume of isopentyl alcohol used = 5.0mL 1b. Density of isoamyl alcohol = ...0...112..... g/mL 3.96 5.0ml = 0.792 Mass of isopentyl alcohol used (show work) = 3.967 23.239.273.90 IC. Volume of glacial acetic acid used = 7.0 mL Density of acetic acid = ...1.2...... g/mL 1.68 Mass of glacial acetic acid used (calculate; show work) = 21 28-07-19.38-268 1d. Mass of the collection R.B flask_ 96.02 .......9 Mass of...
my
actual yield of banana pil is 0.297 need theorticla tield and
percnet yield use isopentyl alcohol
150 ml of alcohol 17 ml acetic acid Iml concentrated sulfuric acid 2 or 3 boiling base in a fiat bottom flask 17.64 gr banana oil need percent yield and theoretical yield of banana oil You need to calculate it with isopentyl alcohol no acetic acid. Then convert mmols to moles, so you just need divide the mmmols by 1000, after that since...
1. Assuming an excess of glacial acetic acid is added, how many moles of isopentyl acetate can be prepared from 0.05 moles of isoamyl alcohol? 2. Assuming an excess of glacial acetic acid is added, how many grams of isopentyl acetate can be prepared from 0.050 moles of isoamyl alcohol? 3. Assuming an excess of glacial acetic acid is added, how man mL of isopentyl acetate can be prepared from 0.050 moles of isoamyl alcohol?
Question #1
Please Complete the following reagent table:
Compound Benzaldehyde Amount moles equivalents MW (g/mol) Density (g/mL) 106.1 138.2 102.1 K2CO3 Acetic anhydride trans-cinnamic acid (1) 4 K2CO3 C7HgO Mol. Wt.: 106.12 bp: 178°C C4H6O3 Mol. Wt.: 102.09 CgHgO2 Mol. Wt.: 148.16 bp: 140°C mp: 135°C
Compound Benzaldehyde Amount moles equivalents MW (g/mol) Density (g/mL) 106.1 138.2 102.1 K2CO3 Acetic anhydride trans-cinnamic acid (1) 4
K2CO3 C7HgO Mol. Wt.: 106.12 bp: 178°C C4H6O3 Mol. Wt.: 102.09 CgHgO2 Mol. Wt.: 148.16...
Question 9 Not yet answered Given the following atomic weights, that the density of acetic acid is 1.05, and that 7.0 g of isoamyl alcohol, 7.4 mL of acetic acid, and 0.5 mL of sulfuric acid make 6.3 g of isoamyl acetate, what is the % yield of isoamyl acetate from its limiting reagent? Give at least two significant figures. C = 12, H = 1, 0 =16 Marked out of 1.00 P Flag question Answer:
In this experiment, we did a Fischer Esterification using excess acetic acid, isopentyl alcohol, and sulfuric acid to form isopentyl acetate. Then sodium bicarbonate and NaCl were used in the extraction step of the experiment. Is there another method we could have used to calculate percent yield other than using the amount of isopentyl acetate? What are the advantages and disadvantages? (Using GC is not the answer we are looking for.)