Find the value of t for the difference between two means based on an assumption of normality and this information about two samples. (Use sample 1 - sample 2. Give your answer correct to two decimal places.)
Sample | Number | Mean | Std. Dev. |
1 | 26 | 37.8 | 13.5 |
2 | 27 | 43.2 | 11.2 |
Test Statistics
We have assumed that the population variances are equal, the t-statistic is computed as follows:
To two decimal places is
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Find the value of t for the difference between two means based on an assumption of...
Find the value of t for the difference between two means based on an assumption of normality and this information about two samples. (Use sample 1 - sample 2. Give your answer correct to two decimal places.) Sample Number Mean Std. Dev. 1 19 37.5 13.8 2 26 42.2 10.6
Find the value of t for the difference between two means based on an assumption of normality and this information about two samples. (Use sample 1 - sample 2. Give your answer correct to two decimal places.) Sample - Number - Mean - Std. Dev. 1 - 27 - 37 - 15 2 - 17 - 42.6 - 11.4
Find the 95% confidence interval for the difference between two means based on this information about two samples. Assume independent samples from normal populations. (Use conservative degrees of freedom.) (Give your answers correct to two decimal places.) Sample - Number - Mean - Std. Dev. 1 - 25 - 36 - 20 2 - 30 - 26 - 21 Lower Limit = Upper Limit =
Find the 98% confidence interval for the difference between two means based on this information about two samples. Assume independent samples from normal populations. (Use conservative degrees of freedom.) (Give your answers correct to two decimal places.) Sample Number Mean Std. Dev. 1 25 31 20 2 13 26 32 Lower Limit Upper Limit
Find the 95% confidence interval for the difference between two means based on this information about two samples. Assume independent samples from normal populations. (Use conservative degrees of freedom.) (Give your answers correct to two decimal places.) Sample Number Mean Std. Dev. 1 10 34 27 2 21 22 31 Lower Limit Upper Limit
Find the 98% confidence interval for the difference between two means based on this information about two samples. Assume independent samples from normal populations. (Use conservative degrees of freedom.) (Give your answers correct to two decimal places.) Sample Number Mean Std. Dev. 1 18 40 30 2 17 28 25 Lower : ??? Upper: ???
Every simulation in this module is based on an assumption about the difference between two population proportions. The population proportions affect the mean and the standard error of the differences in sample proportions. The sample size also affects the standard error. The distribution of differences between sample proportions shown below has mean 0.35, and a standard error of about 0.10. Which of the following did we use to generate this sampling distribution? A.Population proportions of 0.85 and 0.65 with samples...
The MINITAB printout shows a test for the difference in two population means. Two-Sample T-Test and CI: Sample 1, Sample 2 Two-sample T for Sample 1 vs Sample 2 N Mean StDev SE Mean Sample 1 6 28.00 4.00 1.6 Sample 2 9 27.86 4.67 1.6 Difference = mu (Sample 1) - mu (Sample 2) Estimate for difference: 0.14 95% CI for difference: (-4.9, 5.2) T-Test of difference = 0 (vs not =): T-Value = 0.06 P-Value = 0.95...
Use a t-distribution to find a confidence interval for the difference in means Ho = M, - My using the relevant sample results from paired data. Assume the results come from random samples from populations that are approximately normally distributed, and that differences are computed using d = xy - X2. A 99% confidence interval for M, using the paired data in the following table: Case 1 2 3 4 5 Treatment 23 29 31 25 27 1 Treatment 18...
Use a t-distribution to find a confidence interval for the difference in means ud = H - Uy using the relevant sample results from paired data. Assume the results come from random samples from populations that are approximately normally distributed, and that differences are computed using d = x1 - x2. A 99% confidence interval for ud using the paired data in the following table: Case 1 2 3 4 5 Treatment 22 28 31 24 29 Treatment 17 29...