Enter your answer in the provided box. Calculate the following quantity: volume of 2.035 M copper(II)...

Question

Question

Enter your answer in the provided box. Calculate the following quantity: volume of 2.035 M copper(II) nitrate that must be di

science chemistry

Answer 1

Answer #1

The volume of Copper Sulphate required is 162.5 mL

Explanation

According to the equation, V1M1 = V2M2

V1 volume of Copper nitrate used = ?

M1 molarity of Copper nitrate used = 2.035 M

V2 volume of Copper nitrate converted = 538.1 mL

M2 molarity of Copper nitrate converted = 0.6145 M

V1 = V2M2/M1

= (538.1 mL * 0.6145 M) / 2.035 M

= 162.4877 (or) 162.5 mL

Answer 2

Similar Homework Help Questions

5.) Enter your answer in the provided box. Calculate the following quantity: volume of 1.551 M...

5.) Enter your answer in the provided box. Calculate the following quantity: volume of 1.551 M copper(II) nitrate that must be diluted with water to prepare 946.4 mL of a 0.9513 M solution. __?___ mL 6.) . Enter your answer in the provided box. How many milliliters of 0.836 M HCl are needed to react with 28.8 g of CaCO3? 2HCl(aq) + CaCO3(s) → CaCl2(aq) + CO2(g) + H2O(l) __?__ mL 7.) . Enter your answer in the provided box. Sodium...
Calculate the following quantity: volume of 1.184 M copper(II) nitrate that must be diluted with water...

Calculate the following quantity: volume of 1.184 M copper(II) nitrate that must be diluted with water to prepare 204.6 mL of a 0.5422 M solution.
Enter your answer in the provided box. Calculate the composition of the following solution in mass/volume...

Enter your answer in the provided box. Calculate the composition of the following solution in mass/volume %: 40.0 g benzene per 1.00 x 102 mL % benzene Calculate the volume, in L, of water that must be added to dilute 22.9 mL of 10.5 M HCl to 0.0900 M HCl. Enter your answer in the provided box. L water

Enter your answer in the provided box. Calculate the volume of 11.7 M sulfuric acid that...

Enter your answer in the provided box. Calculate the volume of 11.7 M sulfuric acid that must be added to water to prepare 5.879 L of a 0.808 M solution.
Enter your answer in the provided box. Calculate the mass of calcium nitrate in each milliliter...

Enter your answer in the provided box. Calculate the mass of calcium nitrate in each milliliter of a solution prepared by diluting 64.5 ml of 0.920 M calelum nitrate to a final volume of 0.186 L.
Enter your answer in the provided box. Calculate the volume in milliliters of 1.69 M potassium...

Enter your answer in the provided box. Calculate the volume in milliliters of 1.69 M potassium hydroxide that contains 72.3 g of solute. mL solution

Calculate the following quantity: volume of 1.34 M calcium chloride that must be diluted with water...

Calculate the following quantity: volume of 1.34 M calcium chloride that must be diluted with water to prepare 183 mL of a 6.64 × 10^−2 M chloride ion solution.
Enter your answer in the provided box. Lead(II) nitrate is added slowly to a solution that...

Enter your answer in the provided box. Lead(II) nitrate is added slowly to a solution that is 0.0600 M in Cl− ions. Calculate the concentration of Pb2+ ions (in mol / L) required to initiate the precipitation of PbCl2. (Ksp for PbCl2 is 2.40 × 10−4.)
will give thumbs up! 3 attempts left Check my work Enter your answer in the provided...

will give thumbs up! 3 attempts left Check my work Enter your answer in the provided box. points Water is added to 75.0 mL of a 0.992 M KNO, solution until the volume of the solution is exactly 250 mL. What is the concentration of the final solution? eBook Print References 3 attempts left Check my work Enter your answer in the provided box. points A volume of 54.2 mL of a 0.468 M Ca(NO) solution is mixed with 75.5...

Enter your answer in the provided box. Calculate the molarity of a solution prepared by diluting...

Enter your answer in the provided box. Calculate the molarity of a solution prepared by diluting 65.88 mL of 0.469 M potassium chloride to 150.00 mL. IM Enter your answer in the provided box. Calculate the molarity of sodium ion in a solution made by mixing 6.40 mL of 0.619 M sodium chloride with 550.00 mL of 9.02 x 10-2 M sodium sulfate. Assume volumes are additive. M solution