Il see Periodic Table See Hint A solution prepared by dissolving 90.0 mg of a sugar...

Question

Question

science chemistry

Answer 1

Answer #1

Given data

mass of solute = 0.09 g
mass of water = 0.001 kg
depresson in frezing point , dTf= 0.930 C

Kf= 1.86 C/m

Use formula
dTf = Kf* m , where m = molality

dTf = Kf* mass of solute/molar mass of solute * mass of solvent in Kg

molar mass of solute= Kf* mass of solute/dTf * mass of solvent in Kg

= 1.86 C/m * 0.09 g /0.930 C * 0.001 Kg
= 180 g/mol

Answer

molar mass of solute = 180 g/mol
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thanks!. hope it helps

Answer 2

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