Question

The same graph is reprotuced belw for your wierene Tme (e) (3 poluts) Sketch a vector to show the dienction of the net foece on the ma CE this foece is 0 say so. Explain yot cing when it t pont (n (3 pointa) Sketch a vector to is at polat C. If this force is O. say show the direction of the force by the spring on the mass when it Explain your reaning ie (3 pointsl Sketch a vrctor to show the direction of the net force on the maa when it is at peint D. If this forre is 0, y so. Explain your renning (w Aojan

Answer 1

(e) as it is shown in graph at point c' velocity of the mass is maximum value of velocity is not wisible in picture so I assumed it as 'vó Umax= v dumax - O at net that is the acceleration will be zero so at the point į net force will be zero. Hence we can say that point " is the equilibrium point of the mass's harmonic motion 80 Fret = 5+mg = 0 F = -mg pF (force of spring) mass Img { force of gravity)

force by the spring at point Ċ will be towards upward. to understand this let us ossume that initially when there is no mass attached to the spring then it is in equilibrium and the netural length of the spring is 'L' then We attached a mass of mass 'm' then due to the gravitational force on mass m' that %s ma' the spring will expend to a length Ihre) so this will become the new equilibrium position of spring-mass system . so to nullify the value of 'ng' spring will apply a force that will be upward and will be equal to me in magnitude due to the expension in length of spring. F (force of spring) massimo so the force of spring will not be zero cohen mass will be at the point a

let us suppose that the mass of spring at point ĉ is zero then there will be a force due to gravity that is mg hence there will be net acceleration if there will be net acceleration the value of velocity can not be maximumo dumax then t = 0 ) then net fruce = 0 if i de net tone at 191 when mass is at point D then its velocity is zero and reaching towards negative value of velocity. so from the graph we can conclude that mass is going upward from point c to point ò after 'Ď velocity is negative to mass starts to move downward from point 'D'.

- - - - ut - - - - - - - - (e) Net force on the mass when it is at the point Free body diagram of mass * The net force on mass Fret = F + mg ra force of spring due to - contraction mg mg is the force of gravity it will not be zero due to the same direction of both forces.